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Introduction to Linear Polynomials Mathematics Ganita Manjari class 9 in English Medium ncert book solutions Exercise Set 2.5
Introduction to Linear Polynomials Exercise Set 2.5 – Complete NCERT Book Solutions for Class 9 Mathematics Ganita Manjari (English Medium). Get all chapter explanations, extra questions, solved examples and additional practice questions for Introduction to Linear Polynomials Exercise Set 2.5 to help you master concepts and score higher.
Introduction to Linear Polynomials Mathematics Ganita Manjari class 9 in English Medium ncert book solutions Exercise Set 2.5
NCERT Solutions for Class 9 Mathematics Ganita Manjari play an important role in helping students understand the concepts of the chapter Introduction to Linear Polynomials clearly. This chapter includes the topic Exercise Set 2.5, which is essential from both academic and examination point of view. The solutions provided here are prepared strictly according to the latest NCERT syllabus and follow the guidelines of CBSE to ensure accuracy and relevance. Each question is explained in a simple and student-friendly manner so that learners can grasp the concepts without confusion. These NCERT Solutions are useful for regular study, homework help, and exam preparation. All textbook questions are solved step by step to improve problem-solving skills and conceptual clarity. Students of Class 9 studying Mathematics Ganita Manjari can use these solutions to revise important topics, understand difficult questions, and practise effectively before examinations. The chapter Introduction to Linear Polynomials is explained in a structured way, making it easier for students to connect the theory with the topic Exercise Set 2.5. By studying these updated NCERT Solutions for Class 9 Mathematics Ganita Manjari, students can build a strong foundation, boost their confidence, and score better marks in school and board exams.
Introduction to Linear Polynomials
Exercise Set 2.5
Exercise Set 2.5
Q1. A learning platform charges a fixed monthly fee and an additional cost per digital learning module accessed. A student observes that when she accessed 10 modules, her bill was ₹400. When she accessed 14 modules, her bill was ₹500. If the monthly bill y depends on the number of modules accessed, x, according to the relation y = ax + b, find the values of a and b.
Solution:
Given relation:
y = ax + b
When x = 10, y = 400
So,
400 = 10a + b ......(1)
When x = 14, y = 500
So,
500 = 14a + b ......(2)
Subtract equation (1) from equation (2):
500 − 400 = 14a − 10a
100 = 4a
a = 100/4
a = 25
Now substitute a = 25 in equation (1):
400 = 10(25) + b
400 = 250 + b
b = 400 − 250
b = 150
Therefore:
a = 25
b = 150
Q2. A gym charges a fixed monthly fee and an additional cost per hour for using the badminton court. A student using the gym observed that when she used the badminton court for 10 hours, her bill was ₹800. When she used it for 15 hours, her bill was ₹1100. If the monthly bill y depends on the hours of the use of the badminton court, x, according to the relation y = ax + b, find the values of a and b.
Solution:
Given relation:
y = ax + b
When x = 10, y = 800
So,
800 = 10a + b ......(1)
When x = 15, y = 1100
So,
1100 = 15a + b ......(2)
Subtract equation (1) from equation (2):
1100 − 800 = 15a − 10a
300 = 5a
a = 300/5
a = 60
Now substitute a = 60 in equation (1):
800 = 10(60) + b
800 = 600 + b
b = 800 − 600
b = 200
Therefore:
a = 60
b = 200
Q3. Consider the relationship between temperature measured in degrees Celsius (°C) and degrees Fahrenheit (°F), which is given by
°C = a°F + b
Find a and b, given that ice melts at 0 degrees Celsius and 32 degrees Fahrenheit, and water boils at 100 degrees Celsius and 212 degrees Fahrenheit.
Solution:
Given relation:
°C = a°F + b
When °C = 0 and °F = 32
So,
0 = 32a + b ......(1)
When °C = 100 and °F = 212
So,
100 = 212a + b ......(2)
Subtract equation (1) from equation (2):
100 − 0 = 212a − 32a
100 = 180a
a = 100/180
a = 5/9
Now substitute a = 5/9 in equation (1):
0 = 32(5/9) + b
0 = 160/9 + b
b = −160/9
Therefore:
a = 5/9
b = −160/9
Hence, the linear relationship between °C and °F is:
°C = (5/9)°F − 160/9
See other sub-topics of this chapter:
1. Exercise Set 2.1 2. Exercise Set 2.2 3. Exercise Set 2.3 4. Exercise Set 2.4 5. Exercise Set 2.5 6. Exercise Set 2.6 7. Exercise Set 2.7