Class 9 11. Work and Energy Kinetic Energy: NCERT Book Solutions

Class 9 chapter 11. Work and Energy ncert solution for board exams and term 1 and term 2 exams.

NCERT Solutions

All chapters of ncert books Science 11. Work and Energy Kinetic Energy is solved by exercise and chapterwise for class 9 with questions answers also with chapter review sections which helps the students who preparing for UPSC and other competitive exams and entrance exams.

Class 9 chapter 11. Work and Energy ncert solution for board exams and term 1 and term 2 exams. - 11. Work and Energy - Kinetic Energy: NCERT Book Solutions for class 9th. All solutions and extra or additional solved questions for 11. Work and Energy : Kinetic Energy Science class 9th:English Medium NCERT Book Solutions. Class 9 chapter 11. Work and Energy ncert solution for board exams and term 1 and term 2 exams.

11. Work and Energy : Kinetic Energy Science class 9th:English Medium NCERT Book Solutions

NCERT Solutions ⇒ Class 9th ⇒ Science ⇒ Chapter 11. Work and Energy:

Class 9 11. Work and Energy Kinetic Energy: NCERT Book Solutions

NCERT Books Subjects for class 9th Hindi Medium

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11. Work and Energy

Class 9 chapter 11. Work and Energy ncert solution for board exams and term 1 and term 2 exams.

Kinetic Energy

Kinetic Energy: The energy possessed by an object due to its motion is called kinetic energy.

Example of Kinetic Energy:

(i) A falling coconut

(ii) a speeding car

(iii) a rolling stone

(iv) a flying aircraft

(v) flowing water

(vi) blowing wind

(vii) a running athlete

(viii) A moving cricket ball

Main-points:

A moving object can do work.
An object moving faster can do more work than an identical object moving relatively slow.
The kinetic energy of a body moving with a certain velocity is equal to the work done on it to make it acquire that velocity.

Formula for Kinetic Energy:

Consider an object of mass, 'm' moving with a uniform velocity, 'u'. Let it now be displaced through a distance 's' when a constant force, F acts on it in the direction of its displacement.

Its velocity changes from 'u' to 'v'. Then accelaration is 'a'.

Work done, W = f × s ......... (i)

and f = ma ......... (ii)

Now W = ma × s .......... (iii)

According to third equation of motion

2as = v² - u²

So, s = v² - u² / 2a ......... (iv)

Now putting the value of s from (iv) in equation (iii)