Class 6 3. Playing with Numbers Exercise 3.6: NCERT Book Solutions
Class 6 chapter 3. Playing with Numbers ncert solution for board exams and term 1 and term 2 exams.
NCERT Solutions
All chapters of ncert books Mathematics 3. Playing with Numbers Exercise 3.6 is solved by exercise and chapterwise for class 6 with questions answers also with chapter review sections which helps the students who preparing for UPSC and other competitive exams and entrance exams.
Class 6 chapter 3. Playing with Numbers ncert solution for board exams and term 1 and term 2 exams. - 3. Playing with Numbers - Exercise 3.6: NCERT Book Solutions for class 6th. All solutions and extra or additional solved questions for 3. Playing with Numbers : Exercise 3.6 Mathematics class 6th:English Medium NCERT Book Solutions. Class 6 chapter 3. Playing with Numbers ncert solution for board exams and term 1 and term 2 exams.
3. Playing with Numbers : Exercise 3.6 Mathematics class 6th:English Medium NCERT Book Solutions
Class 6 chapter 3. Playing with Numbers ncert solution for board exams and term 1 and term 2 exams. - 3. Playing with Numbers - Exercise 3.6: NCERT Book Solutions for class 6th. All solutions and extra or additional solved questions for 3. Playing with Numbers : Exercise 3.6 Mathematics class 6th:English Medium NCERT Book Solutions.
Class 6 3. Playing with Numbers Exercise 3.6: NCERT Book Solutions
NCERT Books Subjects for class 6th Hindi Medium
3. Playing with Numbers
Class 6 chapter 3. Playing with Numbers ncert solution for board exams and term 1 and term 2 exams.
Exercise 3.6
Exercise -3.6
Q1. Find the H.C.F. of the following numbers:
(f) 34, 102
Solutions:
Prime factorization of 34
= 2 × 17
Prime factorization of 102
= 2 × 3 × 17
HCF of 34 and 102 is 2 × 17
= 34
(g) 70, 105, 175
Solution:
Prime factorization of 70
= 2 × 5 × 7
Prime factorization of 105
= 3 × 5 × 7
Prime factorization of 175
= 5 × 5 × 7
H.C.F. (70, 105, 175)
= 5 × 7
= 35
(h) 91, 112, 49
Solution:
Prime factorization of 91
= 7 × 13
Prime factorization of 112
= 2 × 2 × 2 × 2 × 7
Prime factorization of 49
= 7 × 7
H.C.F. (91, 112, 49) = 7
(i) 18, 54, 81
Solution:
Prime factorization of 18
= 2 × 3 × 3
Prime factorization of 54
= 2 × 3 × 3 × 3
Prime factorization of 81
= 3 × 3 × 3 × 3
H.C.F. = 3 × 3 = 9
(j) 12, 45, 75
Solution:
Prime factorization of 12
= 2 × 2 × 3
Prime factorization of 45
= 3 × 3 × 5
Prime factorization of 75
= 3 x 5 x 5
H.C.F. = 1 × 3
= 3
Q2. What is the H.C.F. of two consecutive:
(a) numbers?
(b) even numbers?
(c) odd numbers?
Solution:
(a) H.C.F. of two consecutive numbers be 1.
(b) H.C.F. of two consecutive even numbers be 2.
(c) H.C.F. of two consecutive odd numbers be 1.
Q3. H.C.F. of co-prime numbers 4 and 15 was found as follows by factorization:
4 = 2 × 2 and
15 = 3 × 5 since there is no common prime factor, so H.C.F. of 4 and 15 is 0. Is the answer correct? If not, what is the correct H.C.F.?
Solution: No. The correct H.C.F. is 1.
Class 6 chapter 3. Playing with Numbers ncert solution for board exams and term 1 and term 2 exams.
See other sub-topics of this chapter:
Class 6 chapter 3. Playing with Numbers ncert solution for board exams and term 1 and term 2 exams. - 3. Playing with Numbers - Exercise 3.6: NCERT Book Solutions for class 6th. All solutions and extra or additional solved questions for 3. Playing with Numbers : Exercise 3.6 Mathematics class 6th:English Medium NCERT Book Solutions. Class 6 chapter 3. Playing with Numbers ncert solution for board exams and term 1 and term 2 exams.
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Notes And NCERT Solutions
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Mathematics Chapter List
1. Knowing Our Numbers
2. Whole Numbers
3. Playing with Numbers
4. Basic Geometrical Ideas
5. Understanding Elementary Shapes
6. Integers
7. Fractions
8. Decimals
