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13. Surface Areas and Volumes Class 9 Mathematics Solutions English Medium-Exercise 13.3
13. Surface Areas and Volumes Class 9 Mathematics Solutions English Medium-Exercise 13.3 Get chapter-wise detailed explanations, step-by-step answers, important questions and exam-ready study material in Hindi and English medium.
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13. Surface Areas and Volumes Class 9 Mathematics Solutions English Medium-Exercise 13.3
NCERT Solutions for Class 9 are specially prepared according to the latest CBSE syllabus (2026-27) to help students understand every concept clearly. These solutions provide step-by-step explanations, accurate answers, and exam-oriented guidance for all chapters. Class 9 students can improve their problem-solving skills, strengthen conceptual understanding, and prepare confidently for school as well as board examinations. All questions are solved in a simple and easy-to-understand language for both Hindi and English medium learners.
13. Surface Areas and Volumes Class 9 Mathematics Solutions English Medium-Exercise 13.3
NCERT Solutions Class 9 Mathematics English Medium
13. Surface Areas and Volumes
Topic: Exercise 13.3
EXERCISE 13.3
Assume that π = 
, unless stated otherwise.
1. Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area.
Solution:
Diameter = 10.5 cm ? radius = 5.25, height = 10 cm
Curved surface area of cone = πrl
? × 5.25 × 10
? × 52.5
? 165 cm2
2. Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m.
Solution:
Slant height = 21 m , diameter = 24 m ? radius = 12 m
Total surface area of cone = πr(l + r)
3. Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Find
(i) radius of the base and (ii) total surface area of the cone.
Solution:
CSA of cone = 308 cm2, height = 14 cm
(i) CSA of cone = 308 cm2
4. A conical tent is 10 m high and the radius of its base is 24 m. Find
(i) slant height of the tent.
(ii) cost of the canvas required to make the tent, if the cost of 1 m2 canvas is 70.
Solution:
Height = 10 cm, radius = 24 m
l2 = h2 + r2
l2 = 102 + 242
l =
l = 26 m
(ii) curved surface area of cone = πrl
5. What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (Use π = 3.14).
Solution:
Wide = 3 m , height = 8 , radius = 6 m
l2 = r2 + h2
l2 = 62 + 82
l =
l = 10 m
Curved surface area of cone = πrl
? 3.14 × 6 × 10
? 31.4 × 6
? 188.4 m2
6. The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white-washing its curved surface at the rate of 210 per 100 m2.
Solution:
Length = 25 m, diameter = 14 m, radius = 7 m
Curved surface area of cone = πrl
7. A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.
Solution:
Radius = 7 cm, height = 24 cm
l2 = r2 + h2
l2 = 72 + 242
8. A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is 12 per m2, what will be the cost of painting all these cones? (Use π = 3.14 )
Solution:
Diameter = 40 cm, radius = 20 cm, height = 1 m
l2 = r2 + h2
l2 = 0.22 + 12
All Topics From 13. Surface Areas and Volumes
See other sub-topics of this chapter:
1. Exercise 13.1 2. Exercise 13.2 3. Exercise 13.3 4. Exercise 13.4 5. Exercise 13.5 6. Exercise 13.6 7. Exercise 13.7 8. Exercise 13.8 9. Exercise 13.9NCERT Solutions Class 9 Hindi and English Medium – Complete Study Material
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