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4. Linear Equation In Two Variables Mathematics class 9 in English Medium ncert book solutions Exercise 4.2
4. Linear Equation In Two Variables Exercise 4.2 – Complete NCERT Book Solutions for Class 9 Mathematics (English Medium). Get all chapter explanations, extra questions, solved examples and additional practice questions for 4. Linear Equation In Two Variables Exercise 4.2 to help you master concepts and score higher.
4. Linear Equation In Two Variables Mathematics class 9 in English Medium ncert book solutions Exercise 4.2
NCERT Solutions for Class 9 Mathematics play an important role in helping students understand the concepts of the chapter 4. Linear Equation In Two Variables clearly. This chapter includes the topic Exercise 4.2, which is essential from both academic and examination point of view. The solutions provided here are prepared strictly according to the latest NCERT syllabus and follow the guidelines of CBSE to ensure accuracy and relevance. Each question is explained in a simple and student-friendly manner so that learners can grasp the concepts without confusion. These NCERT Solutions are useful for regular study, homework help, and exam preparation. All textbook questions are solved step by step to improve problem-solving skills and conceptual clarity. Students of Class 9 studying Mathematics can use these solutions to revise important topics, understand difficult questions, and practise effectively before examinations. The chapter 4. Linear Equation In Two Variables is explained in a structured way, making it easier for students to connect the theory with the topic Exercise 4.2. By studying these updated NCERT Solutions for Class 9 Mathematics, students can build a strong foundation, boost their confidence, and score better marks in school and board exams.
4. Linear Equation In Two Variables
Exercise 4.2
Chapter 4. Linear Equation In Two Variables
Exercise 4.2
1. Which one of the following options is true, and why?
y = 3x + 5 has
(i) a unique solution, (ii) only two solutions,
Solution
(iii) infinitely many solution, because we can put many value of x and can get many solution of y.
2. Write four solutions for each of the following equations:
(i) 2x + y = 7
(ii) πx + y = 9
(iii) x = 4y
Solution
3. Check which of the following are solutions of the equation x – 2y = 4 and which are not:
(i) (0, 2)
(ii) (2, 0)
(iii) (4, 0)
Solution :
x = 4 + 2y
(i) (0,2)
Putting value of x and y
= 0 = 4 + 2(2)
= 0 = 4 + 4 = 0 = 8, hence it is not a solution of eq
(ii) (2,0)
Putting value of x and y
= 2 = 4 + 2(0) = 2 = 4, hence it is also not a solution of eq
(iii) (4,0)
Putting value of x and y
= 4 = 4 + 2(0) = 4 = 4, hence it is a solution of eq
(v) (1,1)
Putting value of x and y
= 1 = 4 + 2(1) = 1= 6, hence, it is not a solution of eq
4. Find the value of k, if x = 2, y = 1 is a solution of the equation 2x + 3y = k.
Solution :
2x + 3y = k
Putting the value of x and y
2(2) + 3(1) = k = 4+3 = k = k = 7
See other sub-topics of this chapter:
1. Exercise 4.1 2. Exercise 4.2 3. Exercise 4.3 4. Exercise 4.4