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Introduction to Probability Mathematics Ganita Manjari class 9 in English Medium ncert book solutions Exercise Set 7.3
Introduction to Probability Exercise Set 7.3 – Complete NCERT Book Solutions for Class 9 Mathematics Ganita Manjari (English Medium). Get all chapter explanations, extra questions, solved examples and additional practice questions for Introduction to Probability Exercise Set 7.3 to help you master concepts and score higher.
Introduction to Probability Mathematics Ganita Manjari class 9 in English Medium ncert book solutions Exercise Set 7.3
NCERT Solutions for Class 9 Mathematics Ganita Manjari play an important role in helping students understand the concepts of the chapter Introduction to Probability clearly. This chapter includes the topic Exercise Set 7.3, which is essential from both academic and examination point of view. The solutions provided here are prepared strictly according to the latest NCERT syllabus and follow the guidelines of CBSE to ensure accuracy and relevance. Each question is explained in a simple and student-friendly manner so that learners can grasp the concepts without confusion. These NCERT Solutions are useful for regular study, homework help, and exam preparation. All textbook questions are solved step by step to improve problem-solving skills and conceptual clarity. Students of Class 9 studying Mathematics Ganita Manjari can use these solutions to revise important topics, understand difficult questions, and practise effectively before examinations. The chapter Introduction to Probability is explained in a structured way, making it easier for students to connect the theory with the topic Exercise Set 7.3. By studying these updated NCERT Solutions for Class 9 Mathematics Ganita Manjari, students can build a strong foundation, boost their confidence, and score better marks in school and board exams.
Introduction to Probability
Exercise Set 7.3
EXERCISE SET 3.3 (SOLVED)
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Prove that the following rational numbers are equal:
(i) 2/3 and 4/6
4/6 = 2÷2 / 6÷2 = 2/3
Hence equal.
(ii) 5/4 and 10/8
10/8 = 10÷2 / 8÷2 = 5/4
Hence equal.
(iii) -3/5 and -6/10
-6/10 = -6÷2 / 10÷2 = -3/5
Hence equal.
(iv) 9/3 and 3
9/3 = 3
Hence equal.
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Find the sum:
(i) 2/5 + 3/10
= 4/10 + 3/10
= 7/10
(ii) 7/12 + 5/8
LCM = 24
= 14/24 + 15/24
= 29/24
(iii) -4/7 + 3/14
= -8/14 + 3/14
= -5/14
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Find the difference:
(i) 5/6 - 1/4
LCM = 12
= 10/12 - 3/12
= 7/12
(ii) 11/8 - 3/4
= 11/8 - 6/8
= 5/8
(iii) -7/9 - (-2/3)
= -7/9 + 2/3
= -7/9 + 6/9
= -1/9
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Find the product:
(i) 2/3 × 3/10
= 6/30
= 1/5
(ii) 7/11 × 5/8
= 35/88
(iii) -4/7 × 5/14
= -20/98
= -10/49
-
Find the quotient:
(i) 2/3 ÷ 3/10
= 2/3 × 10/3
= 20/9
(ii) 7/11 ÷ 5/8
= 7/11 × 8/5
= 56/55
(iii) -4/7 ÷ 5/14
= -4/7 × 14/5
= -8/5
-
Show that:
(1/2 + 3/4) × 8/3 = 1/2 × 8/3 + 3/4 × 8/3
LHS:
= (2/4 + 3/4) × 8/3
= 5/4 × 8/3
= 10/3
RHS:
= 4/3 + 2
= 10/3
Hence LHS = RHS.
-
Simplify using distributive property:
7/9 (6/7 - 3/4)
= 7/9 × 6/7 - 7/9 × 3/4
= 2/3 - 7/12
= 8/12 - 7/12
= 1/12
-
Find the rational number x:
5/6 (x + 3/5) = 5/6 x + 1/2
LHS:
= 5x/6 + 5/6 × 3/5
= 5x/6 + 1/2
Hence proved.
Source File: turn0file0
See other sub-topics of this chapter:
1. Exercise Set 7.1 2. Exercise Set 7.2 3. Exercise Set 7.3 4. Exercise Set 7.4 5. End-of-Chapter Exercises