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Introduction to Linear Polynomials Mathematics Ganita Manjari class 9 in English Medium ncert book solutions Exercise Set 2.2

Introduction to Linear Polynomials Exercise Set 2.2 – Complete NCERT Book Solutions for Class 9 Mathematics Ganita Manjari (English Medium). Get all chapter explanations, extra questions, solved examples and additional practice questions for Introduction to Linear Polynomials Exercise Set 2.2 to help you master concepts and score higher.

Introduction to Linear Polynomials Mathematics Ganita Manjari class 9 in English Medium ncert book solutions Exercise Set 2.2

Introduction to Linear Polynomials Mathematics Ganita Manjari class 9 in English Medium ncert book solutions Exercise Set 2.2

NCERT Solutions for Class 9 Mathematics Ganita Manjari play an important role in helping students understand the concepts of the chapter Introduction to Linear Polynomials clearly. This chapter includes the topic Exercise Set 2.2, which is essential from both academic and examination point of view. The solutions provided here are prepared strictly according to the latest NCERT syllabus and follow the guidelines of CBSE to ensure accuracy and relevance. Each question is explained in a simple and student-friendly manner so that learners can grasp the concepts without confusion. These NCERT Solutions are useful for regular study, homework help, and exam preparation. All textbook questions are solved step by step to improve problem-solving skills and conceptual clarity. Students of Class 9 studying Mathematics Ganita Manjari can use these solutions to revise important topics, understand difficult questions, and practise effectively before examinations. The chapter Introduction to Linear Polynomials is explained in a structured way, making it easier for students to connect the theory with the topic Exercise Set 2.2. By studying these updated NCERT Solutions for Class 9 Mathematics Ganita Manjari, students can build a strong foundation, boost their confidence, and score better marks in school and board exams.

Introduction to Linear Polynomials

Page 2 of 7

Exercise Set 2.2

Last Update On: 17 May 2026

 

Q1. Find the value of the linear polynomial 5x – 3 if:
(i) x = 0 (ii) x = –1 (iii) x = 2

Solutions: 

P(x) = 5x - 3 

(i) x = 0 

P(0) = 5(0) - 3 

        = 0 - 3 

        = - 3 Ans 

(ii) x = -1 

P(-1) = 5(-1) - 3 

        = -5 - 3 

        = - 8 Ans 

(iii) x = 2 

P(2) = 5(2) - 3 

        = 10 - 3 

        = 7 Ans 

Q2. Find the value of the quadratic polynomial 7s2 – 4s + 6 if:
(i) s = 0 (ii) s = –3 (iii) s = 4

Solution: 

P(s) = 7s2 - 4s + 6 

(i) s = 0 

P(0) = 7(0)2 - 4(0) + 6 

        = 0 - 0 + 6 

        = 6 Ans

(ii) s = –3 

P(–3) = 7(–3)2 - 4(–3) + 6 

        = 63 + 12 + 6 

        = 81 Ans

(iii) s = 4 

P(4) = 7(4)2 - 4(4) + 6 

        = 112 - 16 + 6 

        = 118 - 16 

        = 102 Ans

Q3. The present age of Salil’s mother is three times Salil’s present age. After 5 years, their ages will add up to 70 years. Find their present ages.

Solution: 

Let the Salil's present Age be x 

Salil's Mother present age = 3x 

After 5 years

Salil's age = x + 5 

Salil's mother age = 3x + 5 

So, 

Therefore, Salil's Present Age = 15 years 

Salil's Mother Present Age = 3 x 15 = 45 years

Q4. The difference between two positive integers is 63. The ratio of the two integers is 2:5. Find the two integers.

Solution: 

Ratio of the two integers = 2 : 5 

Let the first integer be 2x 

And the second integer be 5x 

So, 5x - 2x = 63 

3x = 63 

x = 63/3 

x = 21 

The first integer = 2 x 21 = 42

The second integer = 5 x 21 = 105 

Q5. Ruby has 3 times as many two-rupee coins as she has five rupee-coins. If she has a total 88, how many coins does she have of each type?

Solution: 

Let the number of five-rupee coins be x.

Then, the number of two-rupee coins will be 3x.

Value of five-rupee coins = 5x

Value of two-rupee coins = 2(3x)

According to the question:

5x + 2(3x) = 88

Now solve:

5x + 6x = 88

11x = 88

x = 88/11

x = 8

So, number of five-rupee coins = 8

Number of two-rupee coins = 3 × 8 = 24

Therefore:

Five-rupee coins = 8

Two-rupee coins = 24

Q6. A farmer cuts a 300 feet fence into two pieces of different sizes. The longer piece is four times as long as the shorter piece. How long are the two pieces?

Solution: 

Let the length of the shorter piece be x feet.

Then, the length of the longer piece will be 4x feet.

According to the question:

x + 4x = 300

Now solve:

5x = 300

x = 300/5

x = 60

So, length of the shorter piece = 60 feet

Length of the longer piece = 4 × 60

= 240 feet

Therefore:

Shorter piece = 60 feet

Longer piece = 240 feet

Q7. If the length of a rectangle is three more than twice its width and its perimeter is 24 cm, what are the dimensions of the rectangle?

Solution:

Let the width of the rectangle be x cm.

Then, the length of the rectangle will be 2x + 3 cm.

Perimeter of rectangle = 2(length + width)

According to the question:

2[(2x + 3) + x] = 24

Now solve:

2(3x + 3) = 24

6x + 6 = 24

6x = 24 − 6

6x = 18

x = 18/6

x = 3

So, width of the rectangle = 3 cm

Length of the rectangle = 2(3) + 3

= 6 + 3

= 9 cm

Therefore:

Width = 3 cm

Length = 9 cm

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