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2. Whole Numbers Mathematics class 6 in English Medium ncert book solutions Exercise 2.2
2. Whole Numbers Exercise 2.2 – Complete NCERT Book Solutions for Class 6 Mathematics (English Medium). Get all chapter explanations, extra questions, solved examples and additional practice questions for 2. Whole Numbers Exercise 2.2 to help you master concepts and score higher.
2. Whole Numbers Mathematics class 6 in English Medium ncert book solutions Exercise 2.2
NCERT Solutions for Class 6 Mathematics play an important role in helping students understand the concepts of the chapter 2. Whole Numbers clearly. This chapter includes the topic Exercise 2.2, which is essential from both academic and examination point of view. The solutions provided here are prepared strictly according to the latest NCERT syllabus and follow the guidelines of CBSE to ensure accuracy and relevance. Each question is explained in a simple and student-friendly manner so that learners can grasp the concepts without confusion. These NCERT Solutions are useful for regular study, homework help, and exam preparation. All textbook questions are solved step by step to improve problem-solving skills and conceptual clarity. Students of Class 6 studying Mathematics can use these solutions to revise important topics, understand difficult questions, and practise effectively before examinations. The chapter 2. Whole Numbers is explained in a structured way, making it easier for students to connect the theory with the topic Exercise 2.2. By studying these updated NCERT Solutions for Class 6 Mathematics, students can build a strong foundation, boost their confidence, and score better marks in school and board exams.
2. Whole Numbers
Exercise 2.2
Exercise-2.2
Q1. Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
Solution: 837 + 208 + 363
= (837 + 208) + 363
= 1045 + 363
= 1408
Or Second Method
= 837 + 363 + 208
= (837 + 363) + 208
= 1200 + 208
= 1408
(b) 1962 + 453 + 1538 + 647
Solution: 1962 + 453 + 1538 + 6477
= (1962 + 453) + (1538 + 647)
= 2415 + 2185
= 4600
Or Second Method
= 1962 + 453 + 1538 + 6477
= (1538 + 1962) + (453 + 647)
= 3500 + 1100
= 4600
Q2. Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
(b) 4 × 166 × 25
(c) 8 × 291 × 125
(d) 625 × 279 × 16
(e) 285 × 5 × 60
(f) 125 × 40 × 8 × 25
Solution:
(a) 2 x 1768 x 50
Solution:
2 x 50 x 1768
= (2 x 50) x 1768
= 100 x 1768
= 176800
(b) 4 x 166 x 25
Solution:
4 x 25 x 166
= (4 x 25) x 166
= 100 x 166
= 16600
(c) 8 x 291 x 125
Solution:
8 x 125 x 291
= 1000 x 291`
= 291000
(d) 125 x 40 x 8 x 25
Solution:
125 x 8 x 40 x 25
= (125 x 8) x (40 x 25)
= 1000 x 1000
= 1000000
(e) 285 × 5 × 60
Solution:
285 × 5 × 60
= 285 × (5 × 60)
= 285 × 300
= 85500
(f) 125 × 40 × 8 × 25
Solution:
125 × 40 × 8 × 25
= (125 × 8) × (40 × 25)
= 1000 × 1000
= 1000000
Q3. Find the value of the following:
(a) 297 × 17 + 297 × 3
Solution:
297 x (17 + 3)
= 297 x 20
= 5940
(b) 54279 × 92 + 8 × 54279
Solution:
54279 x (92 + 8)
= 54279 x 100
= 5427900
(c) 81265 × 169 – 81265 × 69
Solution:
81265 × 169 – 81265 × 69
= 81265 (169 – 69)
= 81265 (100)
= 8126500
(d) 3845 × 5 × 782 + 769 × 25 × 218
Solution:
3845 × 5 × 782 + 769 × 25 × 218
= 3845 × 5 × 782 + 769 × 5 × 5 × 218
= 3845 × 5 × 782 + 3845 × 5 × 218
= 3845 × 5 (782 + 218)
= 19225 × 1000
= 19225000
Q4. Find the product using suitable properties.
(a) 738 × 103
(b) 854 × 102
(c) 258 × 1008
(d) 1005 × 168
Solution:
(a) 738 × 103
= 738 (100 + 3)
= 738 × 100 + 738 × 3
= 73800 + 2214
= 76014
Solution:
(b) 854 × 102
= 854(100 + 2)
= 854 × 100 + 854 × 2
= 85400 + 1708
= 87108
Solution:
(c) 258 × 1008
= 258(1000 + 8)
= 258 × 1000 + 258 × 8
= 258000 + 2064
= 260064
Solution:
(d) 1005 × 168
= (1000 + 5) x 168
= 1000 x 168 + 5 x 168
= 168000 + 840
= 168840
5. A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?
Solution: Taxi driver filled his car petrol tank on Monday = 40 L
He filled the petrol tank on Tuesday = 50 L
The petrol costs per liter = 44 Rs
He spend in all on petrol = (40 + 50) x 44
= 90 x 44
= 3960 Rs
6. A vendor supplies 32 liters of milk to a hotel in the morning and 68 liters of milk in the evening. If the milk costs Rs 15 per liter, how much money is due to the vendor per day?
Solution: A vendor supplies milk to a hotel in the morning = 32 liters
=> A vendor supplies milk to a hotel in the evening = 68 liters
=> The cost of milk per liter = Rs 15
7. Match the following:
Solution:
(i) ----------- (c)
(ii) ---------- (a)
(iii) ---------- (b)