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8. Binomial Theorem Mathematics class 11 in English Medium ncert book solutions Exercise 8.2
8. Binomial Theorem Exercise 8.2 – Complete NCERT Book Solutions for Class 11 Mathematics (English Medium). Get all chapter explanations, extra questions, solved examples and additional practice questions for 8. Binomial Theorem Exercise 8.2 to help you master concepts and score higher.
8. Binomial Theorem Mathematics class 11 in English Medium ncert book solutions Exercise 8.2
NCERT Solutions for Class 11 Mathematics play an important role in helping students understand the concepts of the chapter 8. Binomial Theorem clearly. This chapter includes the topic Exercise 8.2, which is essential from both academic and examination point of view. The solutions provided here are prepared strictly according to the latest NCERT syllabus and follow the guidelines of CBSE to ensure accuracy and relevance. Each question is explained in a simple and student-friendly manner so that learners can grasp the concepts without confusion. These NCERT Solutions are useful for regular study, homework help, and exam preparation. All textbook questions are solved step by step to improve problem-solving skills and conceptual clarity. Students of Class 11 studying Mathematics can use these solutions to revise important topics, understand difficult questions, and practise effectively before examinations. The chapter 8. Binomial Theorem is explained in a structured way, making it easier for students to connect the theory with the topic Exercise 8.2. By studying these updated NCERT Solutions for Class 11 Mathematics, students can build a strong foundation, boost their confidence, and score better marks in school and board exams.
8. Binomial Theorem
Exercise 8.2
Exercise 8.2
Find the coefficient of
Q1. x5 in (x + 3)8
Solution:
(x + 3)8
General term nCr an-r br
n = 8, then
8Cr x8-r 3r ⇒ x5 = x8-r
5 = 8-r
∴ r = 8-5 = 3
8C3 x8-3 33 = 8C3 x5 33
Coefficient in x5 = 8C3 33
= 1512
Q2. a5b7 in (a-2b)12
Solution:
(a-2b)12
General Term Tr+1 = nCr an-r br
12Cr a12-r br
∴12 – r = 5 ⇒ r = 12 – 5 = 7
a5b7 is 8 term
T8 = 12C7 a5 b7
= 12C7 a5 (-2b)7
= - 72 × 11 × 27
= - 72 × 11 × 128 = - 101376
Write the general term in the expansion of
Q3. (x2 - y)6
Solution:
General term of (x2 - y)6
n = 6, a = x2, b = (-y)
General Term Tr +1 = nCr an-r br
= 6Cr (x2)6-r (-y)r
=
See other sub-topics of this chapter:
1. Exercise 8.1 2. Exercise 8.2 3. Miscellaneous Exercise on Chapter - 8